void *memmove(void *dest, const void *src, size_t n);
The memmove() function copies n bytes from memory area src to memory
area dest. The memory areas may overlap: copying takes place as though
the bytes in src are first copied into a temporary array that does not
overlap src or dest, and the bytes are then copied from the temporary
array to dest.
The memmove() function returns a pointer to dest.
SVr4, 4.3BSD, C89, C99, POSIX.1-2001.
bcopy(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)
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GNU 1993-04-10 MEMMOVE(3)
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